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42. (a) The receptacle is a volume of (40 cm)(40 cm)(30 cm) = 48000 cm
3
= 48 L =
(48)(16)/11.356 = 67.63 standard bottles, which is a little more than 3 nebuchadnezzars
(the largest bottle indicated).
The remainder, 7.63 standard bottles, is just a little less
than 1 methuselah. Thus, the answer to part (a) is 3 nebuchadnezzars and 1 methuselah.
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This note was uploaded on 09/03/2009 for the course PHYS 1200 taught by Professor Stoler during the Spring '06 term at Rensselaer Polytechnic Institute.
 Spring '06
 Stoler
 Physics

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