ch02-p015 - 15. We use Eq. 2-4. to solve the problem. (a)...

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15. We use Eq. 2-4. to solve the problem. (a) The velocity of the particle is v dx dt d dt tt t == −+ = + () . 41 2 3 1 26 2 Thus, at t = 1 s, the velocity is v = (–12 + (6)(1)) = –6 m/s. (b) Since v < 0, it is moving in the negative x direction at t = 1 s. (c) At t = 1 s, the speed is | v | = 6 m/s. (d) For 0 < t < 2 s, | v | decreases until it vanishes. For 2 < t < 3 s, | v | increases from zero to the value it had in part (c). Then, |
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