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26. We take +
x
in the direction of motion, so
v
0
= +24.6 m/s and
a
= – 4.92 m/s
2
. We also
take
x
0
= 0.
(a) The time to come to a halt is found using Eq. 211:
0
2
24.6m/s
05
.
0
0
s
4.92m/s
.
va
t
t
−
=+
¡
==
(b) Although several of the equations in Table 21 will yield the result, we choose Eq.
216 (since it does not depend on our answer to part (a)).
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This note was uploaded on 09/03/2009 for the course PHYS 1200 taught by Professor Stoler during the Spring '06 term at Rensselaer Polytechnic Institute.
 Spring '06
 Stoler
 Physics

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