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32. We choose the positive direction to be that of the initial velocity of the car (implying
that
a
< 0 since it is slowing down). We assume the acceleration is constant and use Table
21.
(a) Substituting
v
0
= 137 km/h = 38.1 m/s,
v
= 90 km/h = 25 m/s, and
a
= –5.2 m/s
2
into
v
=
v
0
+
at
, we obtain
t
=
−
−
=
25
38
52
25
2
m/s
s
.
..
(b) We take the car to be at
x
= 0 when the brakes
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 Spring '06
 Stoler
 Physics, Acceleration

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