32. We choose the positive direction to be that of the initial velocity of the car (implying thata< 0 since it is slowing down). We assume the acceleration is constant and use Table 2-1.(a) Substituting v0= 137 km/h = 38.1 m/s, v= 90 km/h = 25 m/s, and a= –5.2 m/s2into v=v0+ at, we obtain t=−−=253852252m/ss...(b) We take the car to be at x= 0 when the brakes
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