ch02-p032 - 32 We choose the positive direction to be that...

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32. We choose the positive direction to be that of the initial velocity of the car (implying that a < 0 since it is slowing down). We assume the acceleration is constant and use Table 2-1. (a) Substituting v 0 = 137 km/h = 38.1 m/s, v = 90 km/h = 25 m/s, and a = –5.2 m/s 2 into v = v 0 + at , we obtain t = = 25 38 52 25 2 m/s s . .. (b) We take the car to be at x = 0 when the brakes
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