ch02-p033 - 33. The problem statement (see part (a)...

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(a) We take x 0 = 0, and solve x = v 0 t + 1 2 at 2 (Eq. 2-15) for the acceleration: a = 2( x v 0 t )/ t 2 . Substituting x = 24.0 m, v 0 = 56.0 km/h = 15.55 m/s and t = 2.00 s, we find () ( ) 2 2 2 24.0m 15.55m/s 2.00s 3.56m/s , 2.00s a == or 2 | | 3.56 m/s a = . The negative sign indicates that the acceleration is opposite to the direction of motion of the car. The car is slowing down.
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