ch02-p035 - 35(a From the figure we see that x0 = 2.0 m...

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35. (a) From the figure, we see that x 0 = –2.0 m. From Table 2-1, we can apply x x 0 = v 0 t + 1 2 at 2 with t = 1.0 s, and then again with t = 2.0 s. This yields two equations for the two unknowns, v 0 and a : () ( ) ( ) 2 0 2 0 1 0.0 2.0 m 1.0 s 1.0 s 2 1 6.0 m 2.0 m 2.0 s 2.0 s . 2 va −− = + = + Solving these simultaneous equations yields the results
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This note was uploaded on 09/03/2009 for the course PHYS 1200 taught by Professor Stoler during the Spring '06 term at Rensselaer Polytechnic Institute.

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