ch02-p039 - m/s)(5 s) = 100 m, and that of the other train...

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39. The displacement ( Δ x ) for each train is the “area” in the graph (since the displacement is the integral of the velocity). Each area is triangular, and the area of a triangle is 1/2( base) × (height). Thus, the (absolute value of the) displacement for one train (1/2)(40
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Unformatted text preview: m/s)(5 s) = 100 m, and that of the other train is (1/2)(30 m/s)(4 s) = 60 m. The initial gap between the trains was 200 m, and according to our displacement computations, the gap has narrowed by 160 m. Thus, the answer is 200 160 = 40 m....
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