44. Neglect of air resistance justifies setting
a
= –
g
= –9.8 m/s
2
(where
down
is our –
y
direction) for the duration of the fall. This is constant acceleration motion, and we may
use Table 21 (with
Δ
y
replacing
Δ
x
).
(a) Using Eq. 216 and taking the negative root (since the final velocity is downward), we
have
22
0
2
0 2(9.8 m/s )( 1700 m)
183 m/s
vv
g
y
=−
−
Δ =−
−
−
.
Its magnitude is therefore 183 m/s.
(b) No, but it is hard to make a convincing case without more analysis. We estimate the
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This note was uploaded on 09/03/2009 for the course PHYS 1200 taught by Professor Stoler during the Spring '06 term at Rensselaer Polytechnic Institute.
 Spring '06
 Stoler
 Physics, Resistance, Acceleration

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