ch02-p048 - 48 We neglect air resistance which justifies...

Info icon This preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
(c) Using 2 2 0 2 v v gy = (with different values for y and v than before), we solve for the value of y corresponding to maximum height (where v = 0). 2 2 0 2 (3.7 m/s) 0.698 m. 2 2(9.8 m/s ) v y g = = = Thus, the armadillo goes 0.698 – 0.544 = 0.154 m higher. 48. We neglect air resistance, which justifies setting a = – g = –9.8 m/s 2 (taking down as the – y direction) for the duration of the motion. We are allowed to use Table 2-1 (with Δ y replacing
Image of page 1
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern