# ch02-p048 - 48 We neglect air resistance which justifies...

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(c) Using 2 2 0 2 v v gy = (with different values for y and v than before), we solve for the value of y corresponding to maximum height (where v = 0). 2 2 0 2 (3.7 m/s) 0.698 m. 2 2(9.8 m/s ) v y g = = = Thus, the armadillo goes 0.698 – 0.544 = 0.154 m higher. 48. We neglect air resistance, which justifies setting a = – g = –9.8 m/s 2 (taking down as the – y direction) for the duration of the motion. We are allowed to use Table 2-1 (with Δ y replacing
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