ch02-p048 - 48. We neglect air resistance, which justifies...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
(c) Using 22 0 2 vv g y =− (with different values for y and v than before), we solve for the value of y corresponding to maximum height (where v = 0). 2 2 0 2 (3.7 m/s) 0.698 m. ( 9 . 8 m / s ) v y g == = Thus, the armadillo goes 0.698 – 0.544 = 0.154 m higher. 48. We neglect air resistance, which justifies setting a = – g = –9.8 m/s 2 (taking down as the – y direction) for the duration of the motion. We are allowed to use Table 2-1 (with Δ y replacing
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 09/03/2009 for the course PHYS 1200 taught by Professor Stoler during the Spring '06 term at Rensselaer Polytechnic Institute.

Ask a homework question - tutors are online