ch02-p050 - g 2 /2, which requires time = 3.83 s. (a) Thus,...

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50. The full extent of the bolt’s fall is given by y – y o = – 1 2 g t 2 where y y o = –90 m (if upwards is chosen as the positive y direction). Thus the time for the full fall is found to be t = 4.29 s. The first 80% of its free fall distance is given by –72 = –
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Unformatted text preview: g 2 /2, which requires time = 3.83 s. (a) Thus, the final 20% of its fall takes t = 0.45 s. (b) We can find that speed using v = g . Therefore, | v | = 38 m/s, approximately. (c) Similarly, v final = g t | v final | = 42 m/s....
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This note was uploaded on 09/03/2009 for the course PHYS 1200 taught by Professor Stoler during the Spring '06 term at Rensselaer Polytechnic Institute.

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