ch02-p053 - the graph (whereas the 2.0 s in the first...

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53. (a) With upward chosen as the + y direction, we use Eq. 2-11 to find the initial velocity of the package: v = v o + at ¡ 0 = v o – (9.8 m/s 2 )(2.0 s) which leads to v o = 19.6 m/s. Now we use Eq. 2-15: Δ y = (19.6 m/s)(2.0 s) + 1 2 (–9.8 m/s 2 )(2.0 s) 2 20 m . We note that the “2.0 s” in this second computation refers to the time interval 2 < t < 4 in
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Unformatted text preview: the graph (whereas the 2.0 s in the first computation referred to the 0 < t < 2 time interval shown in the graph). (b) In our computation for part (b), the time interval (6.0 s) refers to the 2 < t < 8 portion of the graph: y = (19.6 m/s)(6.0 s) + 1 2 (9.8 m/s 2 )(6.0 s) 2 59 m , or | | 59 m y = ....
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This note was uploaded on 09/03/2009 for the course PHYS 1200 taught by Professor Stoler during the Spring '06 term at Rensselaer Polytechnic Institute.

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