()()220143.9 m1.99 s9.8 m/s1.99 s2v−=−−which leads to v0= 12.3 m/s. (b) The velocity of the stones are given by 0(), (1)yydyvgtvvgtdtdt′ΔΔ′==−==−−−The plot is shown below: 56. (a) We neglect air resistance, which justifies setting a= –g= –9.8 m/s2(taking downas the –ydirection) for the duration of the motion. We are allowed to use Eq. 2-15 (with Δyreplacing Δx) because this is constant acceleration motion. We use primed variables (except t) with the first stone, which has zero initial velocity, and unprimed variables with
This is the end of the preview. Sign up
access the rest of the document.