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()
(
)
2
2
0
1
43.9 m
1.99 s
9.8 m/s
1.99 s
2
v
−=
−
−
which leads to
v
0
= 12.3 m/s.
(b) The velocity of the stones are given by
0
(
)
,
(
1)
yy
dy
vg
t
v
v
g
t
dt
dt
′
ΔΔ
′
==
−
=
=
−
−
−
The plot is shown below:
56. (a) We neglect air resistance, which justifies setting
a
= –
g
= –9.8 m/s
2
(taking
down
as the –
y
direction) for the duration of the motion. We are allowed to use Eq. 215 (with
Δ
y
replacing
Δ
x
) because this is constant acceleration motion. We use primed variables
(except
t
) with the first stone, which has zero initial velocity, and unprimed variables with
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 Spring '06
 Stoler
 Physics, Resistance, Acceleration

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