ch02-p060 - 60. We choose down as the +y direction and set...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
to that. The corresponding distance is y y' = 0.50 h , where y denotes the location of the ground. In these terms, y is the same as h , so we have h y' = 0.50 h or 0.50 h = y' . (a) We find t' and t from Eq. 2-15 (with v 0 = 0): 2 2 12 2 . 2 y yg t t g y t t g ′= ¡ = ¡ = Plugging in y = h and y' = 0.50 h , and dividing these two equations, we obtain t t hg == 2050 2 050 ./ / .. b g Letting t' = t – 1.00 (SI units understood) and cross-multiplying, we find tt t −= ¡ = 100 10 5 0 . . which yields t = 3.41 s. (b) Plugging this result into t = 1 2 2 we find h = 57 m. (c) In our approach, we did not use the quadratic formula, but we did “choose a root” when we assumed (in the last calculation in part (a)) that . = +0.707 instead
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 09/03/2009 for the course PHYS 1200 taught by Professor Stoler during the Spring '06 term at Rensselaer Polytechnic Institute.

Ask a homework question - tutors are online