(a) To find the acceleration due to gravity gpon that planet, we use Eq. 2-15 (with +yup) ()( )2201125 m00 2.5 s2.5 s22ppyy vt gtg−=+¡+so that gp= 8.0 m/s2.(b) That same (max) point on the graph can be used to find the initial velocity. ()00025 m002.5 syyv vtv+¡+Therefore, v0= 20 m/s. 62. The graph shows
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This note was uploaded on 09/03/2009 for the course PHYS 1200 taught by Professor Stoler during the Spring '06 term at Rensselaer Polytechnic Institute.