From 100 to 120 ms, region Chas the shape of a rectangle with area 2Carea (0.0200 s) (50.0 m/s ) = 1.00 m/s.=From 110 to 160 ms, region Dhas the shape of a trapezoid with area 2D1(0.0400 s) (50.0 20.0) m/s1.40 m/s.2=+=Substituting these values into Eq. 2-26, with v0=0 then gives 100 1 50 m/s + 1.00 m/s + 1.40 m/s = 3.90 m/s,v.−=+or1390±m/s.=65. The key idea here is that the speed of the head (and the torso as well) at any given time can be calculated by finding the area on the graph of the head’s acceleration versus time, as shown in Eq. 2-26: 1001area between the acceleration curveand the time axis, from
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This note was uploaded on 09/03/2009 for the course PHYS 1200 taught by Professor Stoler during the Spring '06 term at Rensselaer Polytechnic Institute.