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67. Since
/
vd
xd
t
=
(Eq. 24), then
Δ
xv
d
t
=
z
, which corresponds to the area under
the
v
vs
t
graph. Dividing the total area
A
into rectangular (base
×
height) and triangular
1
2
base
height
×
b
g
areas, we have
AA
A
A
A
tt
t
t
=+
+
+
=+
+
+
F
H
G
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This note was uploaded on 09/03/2009 for the course PHYS 1200 taught by Professor Stoler during the Spring '06 term at Rensselaer Polytechnic Institute.
 Spring '06
 Stoler
 Physics

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