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From 10 to 50 ms, region
B
has the shape of a trapezoid with area
B
1
area =
(0.040 s) (2 + 4) m/s = 0.12 m.
2
Substituting these values into Eq. 225, with
x
0
=0 then gives
1
0
0 0 01 m + 0.12 m = 0.13 m,
x.
−=+
or
1
0 13 m.
=
(b) The speed of the fist reaches a maximum at
t
1
= 120 ms. From 50 to 90 ms, region
C
has the shape of a trapezoid with area
C
1
(0.040 s) (4 + 5) m/s = 0.18 m.
2
From 90 to 120 ms, region
D
has the shape of a trapezoid with area
D
1
(0.030 s) (5 + 7.5) m/s = 0.19 m.
2
Substituting these values into Eq. 225, with
x
0
=0 then gives
1
0
0 0 01 m + 0.12 m + 0.18 m + 0.19 m = 0.50 m,
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This note was uploaded on 09/03/2009 for the course PHYS 1200 taught by Professor Stoler during the Spring '06 term at Rensselaer Polytechnic Institute.
 Spring '06
 Stoler
 Physics

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