ch02-p068 - 68. The key idea here is that the position of...

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From 10 to 50 ms, region B has the shape of a trapezoid with area B 1 area = (0.040 s) (2 + 4) m/s = 0.12 m. 2 Substituting these values into Eq. 2-25, with x 0 =0 then gives 1 0 0 0 01 m + 0.12 m = 0.13 m, x. −=+ or 1 0 13 m. = (b) The speed of the fist reaches a maximum at t 1 = 120 ms. From 50 to 90 ms, region C has the shape of a trapezoid with area C 1 (0.040 s) (4 + 5) m/s = 0.18 m. 2 From 90 to 120 ms, region D has the shape of a trapezoid with area D 1 (0.030 s) (5 + 7.5) m/s = 0.19 m. 2 Substituting these values into Eq. 2-25, with x 0 =0 then gives 1 0 0 0 01 m + 0.12 m + 0.18 m + 0.19 m = 0.50 m,
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This note was uploaded on 09/03/2009 for the course PHYS 1200 taught by Professor Stoler during the Spring '06 term at Rensselaer Polytechnic Institute.

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