ch02-p070 - 70. To solve this problem, we note that...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Similarly, the velocity of particle 2 is 2 22 0 2 20.0 ( 8.00 ) 20.0 4.00 . v v a dt t dt t =+ = + = ³³ The condition that 12 vv = implies 12.0 3.00 20.0 4.00 4.00 12.0 17.0 0 tt t t +=− ¡ +− = which can be solved to give (taking positive root) ( 3 26)/ 2 1.05 s. t =−+ = Thus, the velocity at this time is 12.0(1.05) 3.00 15.6 m/s. == + = 70. To solve this problem, we note that velocity is equal to the time derivative of a
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.
Ask a homework question - tutors are online