Similarly, the velocity of particle 2 is 2220220.0( 8.00 )20.0 4.00 .vva dtt dtt=+=+−=−³³The condition that 12vv=implies 12.03.0020.0 4.004.0012.017.00tttt+=−¡+−=which can be solved to give (taking positive root) ( 326)/ 2 1.05 s.t=−+=Thus, the velocity at this time is 12.0(1.05) 3.00 15.6 m/s.==+=70. To solve this problem, we note that velocity is equal to the time derivative of a
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