(b) Using Eq. 2-2, the magnitude of the average velocity is avg38.1 m5.20 m9.02 m/s4.80 sDhvT++===(c) In our coordinate choices, a positive sign for vavgmeans that the ball is going downward. If, however, upwards had been chosen as the positive direction, then this answer in (b) would turn out negative-valued. (d) We find v0from 2102yvtgtΔ= +with t= Tand Δy= h+ D. Thus, ()209.8 m/s4.80 s5.20 m38.1 m14.5 m/s24.80s2hD gTvT=−=−=(e) Here in our coordinate choices the negative sign means that the ball is being thrown upward.74. (a) Let the height of the diving board be h. We choose downas the +ydirection and set the coordinate origin at the point where it was dropped (which is when we start the
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