m/s2. The displacement (which in this situation is the same as the distance traveled) to the point it stops (v2= 0) is, using Eq. 2-16, 222202(30 m/s)290m.2( 5 m/s )vvaxx=+Δ¡Δ=−=−79. We take +xin the direction of motion, so
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This note was uploaded on 09/03/2009 for the course PHYS 1200 taught by Professor Stoler during the Spring '06 term at Rensselaer Polytechnic Institute.