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Unformatted text preview: it started (the top of the building). (c) Now we use our result from part (a) and plug into y y = v t + 1 2 gt 2 with t = 6.00 s and y = 0 (the ground level). Thus, we have 0 y = (15.68 m/s)(6.00 s) 1 2 (9.8 m/s 2 )(6.00 s) 2 . Therefore, y (the height of the building) is equal to 82.3 m....
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This note was uploaded on 09/03/2009 for the course PHYS 1200 taught by Professor Stoler during the Spring '06 term at Rensselaer Polytechnic Institute.
 Spring '06
 Stoler
 Physics

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