91. We take +xin the direction of motion, so v=FHGIKJ= +601000360016 7km / hm / kms/ hm / sbg.anda> 0. The location where it starts from rest (v0= 0) is taken to be x0= 0. (a) Eq. 2-7 gives aavg= (v– v0)/twhere t= 5.4 s and the velocities are given above. Thus, aavg= 3.1 m/s2.(b) The assumption that
This is the end of the preview.
access the rest of the document.