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Unformatted text preview: = r pq n = r ( . 88)( . 12) 80 = . 03633180 np = (80) ( . 88) = 70 . 4 > 5 , nq = (80)( . 12) = 9 . 6 > 5 Since np and nq are both greater thatn 5, the sampling distribution of b p is approximately normal. 7.109 μ = 160 pounds, σ = 25 pounds, and n = 35 μ x = μ = 160 pounds and σ x = σ √ n = 25 √ 35 = 4 . 22577127 pounds Since n > 30 , x is approximately normally distributed. P ( sum of 35 weights exceeds 6000 pounds ) = P ( mean weight exceeds 6000/35 ) = P ( x > 171 . 43) For x = 171 . 43 : z = ( x − μ ) σ x = (171 . 43 − 160) 4 . 22577127 = 2 . 70 P ( x > 171 . 43) = P ( z > 2 . 70) = 1 − P ( z ≤ 2 . 70) = 1 − . 9965 = . 0035 2...
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 Summer '07
 Guggenberger
 Normal Distribution, 2 minutes, 1 minute, 7 minutes, 4.22577127 pounds

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