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Unformatted text preview: cycle with three processes. The boundary work for each process and the net work of the cycle are to be determined. Properties The properties of air are R = 0.287 kJ/kg.K , k = 1.4 (Table A2a). Analysis For the isothermal expansion process: 3 1 1 m 01341 . kPa) (2000 K) 273 50 kJ/kg.K)(3 287 . ( kg) 15 . ( = + = = P mRT V 3 2 2 m 05364 . kPa) (500 K) 273 50 kJ/kg.K)(3 287 . ( kg) 15 . ( = + = = P mRT kJ 37.18 = = =3 3 3 1 2 1 1 2 1 , m 01341 . m 05364 . ln ) m 41 kPa)(0.013 (2000 ln P W b For the polytropic compression process: 3 3 2 . 1 3 2 . 1 3 3 3 2 2 m 01690 . kPa) (2000 ) m 64 kPa)(0.053 (500 = = = n n P P kJ34.86 ===2 . 1 1 ) m 64 kPa)(0.053 (500 ) m 90 kPa)(0.016 (2000 1 3 3 2 2 3 3 3 2 , n P P W b For the constant pressure compression process: kJ6.97 ===3 3 1 3 1 3 , 0.01690)m 41 kPa)(0.013 (2000 ) ( P W b The net work for the cycle is the sum of the works for each process kJ4.65 =++ = + + =) 97 . 6 ( ) 86 . 34 ( 18 . 37 1 3 , 3 2 , 2 1 , net b b b W W W W Air 2 MPa 350 C...
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 Summer '08
 thermo
 pH

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