ch21_p15 - 15. (a) The distance between q1 and q2 is r12 =...

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1 2 () ( ) 22 2 2 12 2 1 2 1 0.020 0.035 0.015 0.005 0.056 m. rx xy y =− + = + = The magnitude of the force exerted by q 1 on q 2 is 966 12 21 12 8.99 10 3.0 10 4.0 10 || 35 N. (0.056) qq Fk r −− ×× × == = (b) The vector G F 21 is directed towards q 1 and makes an angle θ with the + x axis, where 11 21 1.5 0.5 tan tan 10.3 10 . 2.0 3.5 yy xx §· = ° ° ¨¸ ©¹ (c) Let the third charge be located at ( x 3 , y 3 ), a distance r from q 2 . We note that q 1 , q 2 and q 3 must be collinear; otherwise, an equilibrium position for any one of them would be impossible to find. Furthermore, we cannot place q 3 on the same side of q 2 where we also find q 1 , since in that region both forces (exerted on q 2 by q 3 and q 1 ) would be in the same direction (since q 2 is attracted to both of them). Thus, in terms of the angle found in part
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This note was uploaded on 09/06/2009 for the course PHYSICS 14358 taught by Professor Bolton during the Spring '09 term at Kansas State University.

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