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1
2
()
(
)
22
2
2
12
2
1
2
1
0.020 0.035
0.015 0.005
0.056 m.
rx
xy
y
=−
+
−
=
−
−
+
−
=
The magnitude of the force exerted by
q
1
on
q
2
is
966
12
21
12
8.99 10
3.0 10
4.0 10

35 N.
(0.056)
qq
Fk
r
−−
××
×
==
=
(b) The vector
G
F
21
is directed towards
q
1
and makes an angle
θ
with the +
x
axis, where
11
21
1.5 0.5
tan
tan
10.3
10 .
2.0 3.5
yy
xx
§·
−
−
=
−
°
≈
−
°
¨¸
−
©¹
(c) Let the third charge be located at (
x
3
,
y
3
), a distance
r
from
q
2
. We note that
q
1
,
q
2
and
q
3
must be collinear; otherwise, an equilibrium position for any one of them would be
impossible to find. Furthermore, we cannot place
q
3
on the same side of
q
2
where we also
find
q
1
, since in that region both forces (exerted on
q
2
by
q
3
and
q
1
) would be in the same
direction (since
q
2
is attracted to both of them). Thus, in terms of the angle found in part
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This note was uploaded on 09/06/2009 for the course PHYSICS 14358 taught by Professor Bolton during the Spring '09 term at Kansas State University.
 Spring '09
 Bolton
 Force

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