HW7_sol - 14.22 Defining v1 as the source node: (a) 2k 100k...

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14.22 Defining v 1 as the source node: a () 2 k Ω 100 k Ω= 1.96 k Ω v i v 1 10 6 + 3.54 x 10 3 v i v 1 = v 1 1960 3.541 x 10 3 v i = 4.051 x 10 3 v 1 v 1 = 0.874 v i | A v = 0.874 R in = v i i i = v i 10 6 v i v 1 = 7.94 M Ω Driving the output with current source i x : R out : i x = v 1 10 6 + v 1 2000 + 3.54 x 10 3 v 1 R out = v 1 i x = 247 Ω b R in =∞ g m v gs 2 k Ω 100 k Ω v gs + - + - 1 M Ω v 1 v i R G 14.23 V EQ =− 12 + 12 100 k Ω 100 k Ω+ 100 k Ω 6.00 V R EQ = 100 k Ω 100 k Ω = 50.0 k Ω I B = 0.7 + 6 V 50.0 k 126 4.7 k Ω = 8.25 μ A I C = 1.03 mA V CE =24 2000 I C 4700 I E = 17.1 V Active region is correct. | r π = 125 0.025 V 1.03 mA = 3.03 k Ω r o = 50 + 17.1 V 1.03 mA = 65.1 k Ω R B = R 1 R 2 = 100 k Ω 100 k Ω = 50.0 k Ω R L = R 3 R E r o = 24 k Ω 4.7 k Ω 65.1 k Ω = 3.71 k Ω R in = R B r + β o + 1 R L [] = 50.0 k Ω 3.03 k 126 3.71 k Ω = 45.2 k Ω A v =+ o + 1 R L r + o + 1 R L R in R I + R in = 126 3.71 k Ω 3.03 k 126 3.71 k Ω 50.0 k Ω 500 50.0 k Ω = 0.984 v be = v i R in R I + R in r r + o + 1 R L = 50.0 k Ω 500 50.0 k Ω 3.03 k Ω 3.03 k 126 3.71 k Ω = 6.34
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This note was uploaded on 09/05/2009 for the course ECE 3040 taught by Professor Hamblen during the Spring '07 term at Georgia Institute of Technology.

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HW7_sol - 14.22 Defining v1 as the source node: (a) 2k 100k...

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