HW4_sol - 13.50 IC = oVT r = 75(0.025V ) 10 4 = 187.5 A | Q...

Info iconThis preview shows pages 1–6. Sign up to view the full content.

View Full Document Right Arrow Icon
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 4
Background image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
13.50 I C = β o V T r π = 75 0.025 V () 10 4 Ω = 187.5 μ A | Q - point : 188 A , V CE 0.7 V g m = 40 I C = 40 1.875 x 10 4 = 7.50 mS r o = V A + V CE I C V A I C = 100 V 187.5 A = 533 k Ω 13.53 I C = o V T r = 75 0.025 V 10 6 Ω = 1.875 A Q - point : 1.88 A , V CE 0.7 V g m = 40 I C = 40 1.875 x 10 6 = 75.0 S r o = V A + V CE I C V A I C = 100 V 1.875 A = 53.3 M Ω 13.60 g m = 40 50 A = 2.00 mS r = 100 2.00 mS = 50 k Ω r o = 75 V + 10 V 50 A = 1.70 M Ω R BB = R B r = 100 k Ω 50 k Ω = 33.3 k Ω A v =− 33.3 k Ω 33.3 k Ω+ 0.75 k Ω 2 mS 1.70 M Ω 100 k Ω 100 k Ω 95.0 13.63 g m = 40 1 A = 40 S r = 40 40 S = 1 M Ω r o = 50 + 1.5 1
Background image of page 6
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 6

HW4_sol - 13.50 IC = oVT r = 75(0.025V ) 10 4 = 187.5 A | Q...

This preview shows document pages 1 - 6. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online