HW3_sol - 3.43 j = VT ln N AND 10151020 = 0.025ln = 0.864V...

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3.43 φ j = V T ln N A N D n i 2 = 0.025ln 10 15 10 20 10 20 = 0.864 V w do = 2 ε S q 1 N A + 1 N D j = 2 11.7 () 8.854 x 10 14 1.602 x 10 19 1 10 15 + 1 10 20 0.864 = 1.057 x 10 4 cm C jo " = S w do = 11.7 8.854 x 10 14 1.057 x 10 4 = 9.80x10 -9 F / cm 2 | C j = C jo " A 1 + V R j = 9.80x10 -9 0.05 1 + 5 0.864 = 188 pF 3.45 (a) C D = I D τ T V T = 10 4 A 10 10 s 0.025 V = 400 fF (b) Q = I D T = 10 4 A 10 10 s = 10 fC (c) C D = 25 x 10 3 A 10 10 s 0.025 V = 100 pF Q I D T = 5 x 10 3 A 10 10 s = 0.50 pC
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3.72 (a) (a) D 1 and D 2 forward biased I D 2 = 0 −− 9 () 15 V k Ω = 600 μ A I D 1 = I D 2 6 0 15 V k Ω = 200 A D 1 : 0 V, 200 A D 2 : 0 V, 600 A (b) D 1 forward biased, D 2 reverse biased I D 1 = 6 0 15 V k Ω = 400 A V D 2 =− 9 0 9 V D 1 : 0 V, 400 A D 2 : -9 V, 0 A (c) D 1 reverse biased, D 2 forward biased I D 2 = 6 V 9 V 30 k Ω = 500 A V D 1 = 6 15000 I D 2 1.50 V D 1 : 1.50 V, 0 A D 2 : 0 V, 500 A (d) D 1 and D 2 forward biased I D 2 = 0 6 15 V k Ω = 400 A I D 1 = 9 0 15 V k Ω I D 2 = 200 A D 1 : 0 V, 200 A D 2 : 0 V, 400 A (b) (a) D 1 on, D 2 on : I D 2 = -0.75 0.75 9 15 k Ω = 500 A | I D 1 = 500 A 6 0.75 15 k Ω = 50.0 A D 1 :50 .0 A , 0.75 V D 2 : 500 A , 0.75 V (b) D 1 2
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HW3_sol - 3.43 j = VT ln N AND 10151020 = 0.025ln = 0.864V...

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