CV2101 Chapt 4 - Equilibrium of a Rigid Body

CV2101 Chapt 4 - Equilibrium of a Rigid Body - Equilibrium...

Info iconThis preview shows pages 1–8. Sign up to view the full content.

View Full Document Right Arrow Icon
Chapter 4 quilibrium of a Rigid Body Equilibrium of a Rigid Body
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
1 Conditions for equilibrium 4.1 Conditions for equilibrium Recall that Any system of external forces acting on a rigid body can e reduced to an equivalent force uple system at an arbitrary be reduced to an equivalent force-couple system at an arbitrary point O. or equilibrium the net force as well as the net moment at that For equilibrium, the net force as well as the net moment at that point must be equal to zero. Σ F = 0 and Σ M = 0 O ± External forces include applied loads, support reactions, and the weight of the body ± A body is considered rigid when deformations between its parts are negligible before and after applying a load. 4-2
Background image of page 2
2Free- ody Diagram 4.2 Free Body Diagram To analyze a physical system, first create an idealized model. 1. Isolate the body. 2. Draw an outline shape. 3. Show all the external forces (known & unknown) exert on the body. 4. Apply the equations of equilibrium to solve for any unknowns. Pin support prevents translation 4-3
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
xample 4 1 Example 4.1 Draw the FBD of the uniform beam. The beam has a mass of 100 kg. ixed support prevents translation & rotation Free-body diagram The reactions at the wall are shown as A x , A y and the couple M A . Their sense Fixed support prevents translation & rotation has been assumed. The weight of the beam W = 100× 9.81 = 981 N acts through the center of 4-4 gravity G, which is 3 m from A.
Background image of page 4
xample 4 3 Example 4.3 Two smooth pipes, each having a mass of 300 kg, are supported by the forks of the tractor. Draw a FBD for both pipes together , assuming no friction at all contact surfaces. The weight of the pipe =300×9.81= 2943N passes through the centroid of the body. Free-body diagram The reactions T, F, P are normal to the supporting surface. Internal forces between the pipes are not own as they are a pair of equal but opposite 4-5 shown as they are a pair of equal but opposite collinear forces which cancel each other
Background image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
eactions at support in 2- problems Reactions at support in 2 D problems ypes of No. of unknowns Types of connection Reaction 4-6
Background image of page 6
eactions at support in 2- problems Reactions at support in 2 D problems cont .
Background image of page 7

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 8
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 27

CV2101 Chapt 4 - Equilibrium of a Rigid Body - Equilibrium...

This preview shows document pages 1 - 8. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online