8-twoup - A Scheduling Problem We wish to schedule a set of...

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Unformatted text preview: A Scheduling Problem We wish to schedule a set of jobs on a single server. Each job requires one unit of execution time and has its own deadline. We schedule each job in turn at the latest available time prior to its deadline. If there is no time available prior to a jobs deadline, we dont schedule it. Problem: How do we quickly find the latest available time prior to a jobs deadline? 1 Partial Solution We number the time slots 1 ..n , so that slot i is the last slot prior to time i . We partition the time slots into disjoint sets such that each set contains a time interval in which only the first time slot is available. In order to ensure that the first interval has an available time slot, we include time slot , which is always considered to be available. 2 Needed Operations In order to be able to find the latest available time slot no later than slot i , we must be able to determine which set contains i , and what the available time slot in that set is. With each set we associate a unique representative , which is some element in the set....
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8-twoup - A Scheduling Problem We wish to schedule a set of...

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