Ch22_p13 - E x net = 2 q d 4 πε o d 2 y 2 3/2 = 1.38 × 10 − 10 N/C(b The net electric field points in the – x direction or 180 °

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13. (a) The vertical components of the individual fields (due to the two charges) cancel, by symmetry. Using d = 3.00 m, the horizontal components (both pointing to the – x direction) add to give a magnitude of
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Unformatted text preview: E x , net = 2 q d 4 πε o ( d 2 + y 2 ) 3/2 = 1.38 × 10 − 10 N/C . (b) The net electric field points in the – x direction, or 180 ° counterclockwise from the + x axis....
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This note was uploaded on 09/06/2009 for the course PHYSICS 14358 taught by Professor Bolton during the Spring '09 term at Kansas State University.

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