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2. (a) We note that the electric field points leftward at both points. Using GG Fq E = 0 , and orienting our x axis rightward (so ˆ i points right in the figure), we find G F =+ × − F H G I K J =− × −− 16 10 40 6 4 10 19 18 . # . # C N C iN i c h which means the magnitude of the force on the proton is 6.4 × 10 –18 N and its direction ˆ
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This note was uploaded on 09/06/2009 for the course PHYSICS 14358 taught by Professor Bolton during the Spring '09 term at Kansas State University.
- Spring '09