ch21_p14 - 14. Since the forces involved are proportional...

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14. Since the forces involved are proportional to q , we see that the essential difference between the two situations is F a q B + q C (when those two charges are on the same side) versus F b q B + q C (when they are on opposite sides). Setting up ratios, we have F a F b = q B + q C - q B + q C ¡ 20.14 -2.877 = 1 + r -1 + r where in the last step we have canceled (on the left hand side) 10
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This note was uploaded on 09/06/2009 for the course PHYSICS 14358 taught by Professor Bolton during the Spring '09 term at Kansas State University.

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