Ch21_p11 - 11(a Eq 21-1 gives 20.0 10 C = 1.60N qq F12 = k 1 22 = 8.99 109 N m 2 C2 2 d(1.50m-6 2(b A force diagram is shown as well as our choice

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11. (a) Eq. 21-1 gives () 2 6 92 2 12 12 2 2 20.0 10 C 8.99 10 N m C 1.60N. 1.50m qq Fk d × == × = (b) A force diagram is shown as well as our choice of y axis (the dashed line). The y axis is meant to bisect the line between q 2 and q 3 in order to make use of the symmetry in the problem (equilateral triangle of side length
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This note was uploaded on 09/06/2009 for the course PHYSICS 14358 taught by Professor Bolton during the Spring '09 term at Kansas State University.

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