This preview shows page 1. Sign up to view the full content.
11. (a) Eq. 211 gives
()
2
6
92
2
12
12
2
2
20.0 10 C
8.99 10 N m C
1.60N.
1.50m
qq
Fk
d
−
×
==
×
⋅
=
(b) A force diagram is shown as well as our choice of
y
axis (the dashed line).
The
y
axis is meant to bisect the line between
q
2
and
q
3
in order to make use of the
symmetry in the problem (equilateral triangle of side length
This is the end of the preview. Sign up
to
access the rest of the document.
This note was uploaded on 09/06/2009 for the course PHYSICS 14358 taught by Professor Bolton during the Spring '09 term at Kansas State University.
 Spring '09
 Bolton
 Force

Click to edit the document details