9 - Answers - Paull BIO 212 Problem Set #9 (14 pts) Due on...

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Paull BIO 212 Problem Set #9 (14 pts) Due on April 14/15 Handout #9: bacterial genetics cont./recombinant DNA 1. You have two bacterial strains. The first is Hfr str s met + leu + cys + (where str s refers to sensitivity to the antibiotic streptomycin). The second strain is F- str r met - leu - cys - (where str r refers to resistance to the antibiotic streptomycin). met, leu, and cys are genes required for growth in the absence of methionine, leucine, and cysteine, respectively. a. (1 pt) You plate the Hfr strain on media containing methionine (met), cysteine (cys), and streptomycin. The bacteria do not grow. Why? Because the Hfr strain is sensitive to streptomycin. b. (1 pt) You plate the F- strain on media containing methionine (met), cysteine (cys), and streptomycin. The bacteria do not grow. Why? Because the F- strain has a leu- allele and thus cannot grow in the absence of leucine. c. (2 pts) You plate a mixture of the Hfr strain and the F- strain on media containing methionine (met), cysteine (cys), and streptomycin. Many colonies
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9 - Answers - Paull BIO 212 Problem Set #9 (14 pts) Due on...

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