{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

2800 HW 1 - SOLUTIONS

2800 HW 1 - SOLUTIONS - CH EN 2800 Fundamentals of Process...

Info icon This preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
CH EN 2800 – Fundamentals of Process Engineering Spring 200 8 HOMEWORK #1 SOLUTIONS 1. Book problem 1.2 For these, simply put in the appropriate conversion factors and make sure that the units cancel out. You can find conversion factors inside the front cover of the book. (a) 3 m 4 3 m 3 ft hr lb ft 3.281 m h 1 min 60 g 454 lb m min g 0.04 × = 10 .50 1 (b) day ft day h 24 h 1 s 3600 L 28.32 ft s L 2 3 3 6100 = (c) kg s m m ft 3.2808 kg lb 2.2046 s 3600 24 365 yr cm 100 m in m 0.0254 ft lb s yr cm in 6 2 2 m 2 2 m 2 × = × × -11 10 1.15 2. Book problem 1.7 This is somewhat reminiscent of the old "if a train leaves Chicago at 2:00 travels 80 miles an hour towards Philadelphia…" problem. Basically, what we have to do is determine how many gallons are used for each of the two scenarios and compare them. Knowing that the final measurement will be in gallons will help us set up the problem: gallons should be "on top" in the equations. Essentially, we are converting miles required for the trip to gallons required for the trip, so it should be intuitive that miles should also be "on top" in the equations. ( ) gallons hr gal 2200 miles 525 hr miles 1000 4190 = ( ) gallons hr gal 2000 miles 475 hr miles 1000 4211 = It appears that it would actually take 21 gallons more if you follow the boss's plan.
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon