HW8Soln - Problem 2.8 atm Hg Hg w w oil oil A P d g d g d g...

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Unformatted text preview: Problem 2.8 atm Hg Hg w w oil oil A P d g d g d g P = + + ( ) w w oil oil Hg Hg atm A d g d g d g P P + = ( ) [ ] w oil oil Hg Hg w atm A d d SG d SG g P P + = Specific gravity of mercury is 13.6 ( ) ( ) ( ) ( ) [ ] ft ft ft ft lbm lbfs lbmft s ft P P atm A 5 . 1 10 8 . 1 6 . 13 3 . 62 2 . 32 2 . 32 3 2 2 + = Psig ft lbf P P P gauge atm A 26 . 3 . 37 2 = = = or Psia Psi ft lbf P A 96 . 14 7 . 14 3 . 37 2 = + = Problem 2.14 a. Static force balance in y-direction tan sec sec = k tion x atm tion x bottom W A P A P A. 250 4 4 2 2 = lbf D P D P atm bottom Note P bottom is the pressure at the water level inside the tank Use walk through method to determine P bottom . bottom w w atm P gy gh P = + where y is the height from the opening of the tank to the level of water in the tank B. ( ) y h g P P w atm bottom + = Solve equations A and B for (h-y) ( ) 2 2 2 2 4 . 2196 3 . 15 4 24 250 7 . 14 ft lbf...
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HW8Soln - Problem 2.8 atm Hg Hg w w oil oil A P d g d g d g...

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