HW9Soln - Problem 4.5 By conservation of mass = • + • +...

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Unformatted text preview: Problem 4.5 By conservation of mass = • + • + • ∫ ∫ ∫ out side in dA n v dA n v dA n v Across the inlet and outlet the velocity is constant wrst. area 4 4 6 2 2 = + • + ∫ D π V dA n v D π s m- side Velocity along the side changes linearly according to L z V v side 2 = and the differential area is Ddz dA π = ( ) 4 2 4 6 2 5 2 = + + ∫ = = D π V dz π D L z V D π s m- m . z z D s m D L V 4 6 4 4 = ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ + ( ) s m m m s m V 7 . 1 4 2 . 4 5 . 2 . 5 . 1 = ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ + = Problem 4.7 ( ) = • + ∂ ∂ ∫ ∫ S V dA n v dV t ρ ρ Examine flux at the inlet and outlets. For constant density and velocity across the inlet/outlet ( ) in out S m m dA n v & & − = • ∫ ρ ( ) 8 . 71 481 . 7 1 min 2 min 2 . 19 3 3 = − = • ∫ ft lb gal ft gal lb dA n v S ρ Implies that TOTAL mass of the system is constant = ∂ ∂ = ∂ ∂ ∫ t M dV t total V ρ Mass balance of salt (S) in the tank ( ) = • + ∂ ∂ ∫ S s dA n v t S ρ ( ) gal lb...
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This note was uploaded on 09/07/2009 for the course CBME Kinetics & taught by Professor Lobban during the Spring '09 term at The University of Oklahoma.

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HW9Soln - Problem 4.5 By conservation of mass = • + • +...

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