HW 9 solution - P8-52A BC ABCFio lb...

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Unformatted text preview: P8-52A BC+ABCFio lb molehr-10100.0Tio(F)8080-~PioBtuClb mole F&514447.5,lbMWlb mol12894222,3ilbftρ6367.26520,000RBtuHlb mol A∆=, Energy balance with work term included is:101,1,110()SARiPioABABAFAQ WXHCT TFFXFQ UA Ts Tθθθ--∆=-======-&&%&Substituting into energy balance,{}()()()63525199SSARAFApApBSSARApApBSSARApApBsUA TTWFH XFCCT TUA TTWFHFCCUA T TUA TTWFHTTFCCUABtuWhrTF---∆=+----∆=++----∆=+++-=∴=P8-6A BC+Since the feed is equimolar, CA0 = CB0= .1 mols/dm3CA= CA0(1-X)CB= CB0(1-X)Adiabatic:[( )]30 15 15iRiPPPpCpBpAXH TTTCX CCCCCφ-∆=++∆∆=--=--=%%( )RCBAH THHH∆=--= -41000-(-15000-(-20000) = -6000 cal/mol A15 1530iipABpBcalCCCmol Kθθ=+=+=%6000300300 20030XTX=+=+222(1).01 (1)AArk CXkX-=-=-P8-6 (a)PFRAAACSTRAdXVFrF XVr=-=-For the PFR, FA0 = CA0v= (.1)(2) = .2 mols/dm3See Polymath program P8-6-a.pol.Calculated values of DEQ variables VariableInitial valueMinimal valueMaximal valueFinal value1 X 0 0 0.85 0.85 2 V 0 0 308.2917 308.2917 3 Ca0 0.1 0.1 0.1 0.1 4 Fa0 0.2 0.2 0.2 0.2 5 T 300. 300. 470. 470. 6 k 0.01 0.01 4.150375 4.150375 7 ra -0.0001 -0.0018941 -0.0001 -0.0009338 Differential equations1 d(V)/d(X) = -Fa0 / ra Explicit equations1 Ca0 = .1 2 Fa0 = .2 3 T = 300 + 200 * X 4 k = .01*exp((10000 / 2) * (1 / 300 - 1 / T)) 5 ra = -k * (Ca0 ^ 2) * ((1 - X) ^ 2) V = 308.2917dm3For the CSTR, X = .85, T = 300+(200)(85) = 470 K.k = 4.31 (Using T = 470K in the formula).-rA= .000971 mol/dm3/s3-4.1 2 .85175 dm9.71 10AAF XVrB===-The reason for this difference is that the temperature and hence the rate of reaction remains constant throughout the entire CSTR (equal to the outlet conditions), while for a...
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This note was uploaded on 09/07/2009 for the course CBME Kinetics & taught by Professor Lobban during the Spring '09 term at The University of Oklahoma.

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HW 9 solution - P8-52A BC ABCFio lb...

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