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alc_sol_man_ch09

# alc_sol_man_ch09 - Solutions Manual 9.1 5V NC NO digital...

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Unformatted text preview: Solutions Manual 9.1 5V NC NO digital signal 9.2 NO 5V reset 9.3 V1 V2 circuit 1 circuit 2 9.4 During the transition from 3 (0011) to 4 (0100), any of the following 8 codes could result: 0000, 0001, 0010, 0011, 0100, 0101, 0110, 0111. UHY OLQH ------------------------ ------------------- --------- UHY OLQHV SXOVHV ' -------- ' G' -- 9.5 ------------SXOVH 9.6 \$ G\$ 66 Introduction to Mechatronics and Meaurement Systems Solutions Manual G' but -----' G/ , so -----/ G\$ -----\$ ' ' G/ ------- / ---------------------------------- ' -------- G/ -----/ 9.7 \$ ' -------- 3 --\$ LQ , SVL ( VWHHO ) -( SVL 5 / 5 -------------- / ------------------------- ' 9.8 ( )* \$ 5 9R 3D ' -------- 3 --\$ P 3 1 5 P 3D 5 -( 5 5 5 ) * 5 5 5 5 5 9 H[ ------------------ ------------------ 5 5 5 5 9 H[ 9.9 Combination of the two figures in the chapter. 9 H[ , -------5 9 H[ 9 ------- 9 -------------------- ( ) 9 P\$ 9.10 Introduction to Mechatronics and Measurement Systems 67 Solutions Manual 3 9.11 ,9 P: 5' < 5 * so 5' < 5 * ----------- but 5' / --- , so P -P / < ------------------- ( ) P 9.12 Using MathCAD: Type J Coefficents: c0 c1 c2 0.0488683 19873.1 218615 c3 c4 c5 . 7 1.1569210 . 8 2.6491810 . 9 2.0184410 5 T( V) i= 0 Approximate Sensitivity: T( 0 ) = 0.049 DVDT T( 0.03) = 546.224 0.03 0 T( 0.03) T( 0 ) DVDT = 5.492. 10 5 ci . V i The sensitivity is approximately 0.055 mV / deg C. 68 Introduction to Mechatronics and Meaurement Systems Solutions Manual 9.13 Using MathCAD: Type J Coefficents: c0 c1 c2 0.100861 25727.9 767346 c3 c4 c5 . 7 7.8025610 . 9 9.2474910 . 11 6.9768810 c6 c7 . 13 2.6619210 . 14 3.9407810 7 T( V) i= 0 Approximate Sensitivity: T( 0 ) = 0.101 DVDT T( 0.015) = 302.478 0.015 0 T( 0.015) T( 0 ) T( 0.010) = 213.286 5 ci . V i DVDT = 4.961. 10 The sensitivity is approximately 0.050 mV / deg C. 9.14 Using MathCAD: Type J Coefficents: c0 c1 c2 0.0488683 19873.1 218615 c3 c4 c5 . 7 1.1569210 . 8 2.6491810 . 9 2.0184410 5 T( V) i= 0 V 0 root ( T( V) 200, V) V 200 = 0.011 T V 200 = 200 ci . V i V 200 Introduction to Mechatronics and Measurement Systems 69 Solutions Manual So 9 / 9.15 9 7 / 9 / 97 / 7 ( 97 / ) 9.16 9 7 / 9 / 97 / 7 ( 97 / ) P9 D D 9 / D 9 / D 9 / D 9 / D 9 / P9 9 7 / 9 / & P9 D D 9 / D 9 / D 9 / D 9 / D 9 / P9 9 7 / 9 / & P9 P9 P9 70 Introduction to Mechatronics and Meaurement Systems Solutions Manual 9.17 Using MathCAD: Type J Coefficents: c0 c1 c2 0.0488683 19873.1 218615 c3 c4 c5 . 7 1.1569210 . 8 2.6491810 . 9 2.0184410 5 T( V) i= 0 V 0 root ( T( V) 120, V) 10, V) V 120 = 6.356. 10 V 10 = 5.084. 10 V = 5.848. 10 3 4 3 ci . V i V 120 V 10 V T V 120 = 120 T V 10 = 10 root ( T( V) V 120 V 10 So the change in voltage would be 5.85 mV. 1 --P ---------------NJ 9.18 Q ----Q ----- Q N--P ----------- UDG -----VHF E ------------- NP --------------------------------- ( ) Introduction to Mechatronics and Measurement Systems 71 Solutions Manual (a) [ LQ DFWXDO [ LQ DFWXDO ; LQ UDG PP ------ VHF PP -------- VHF P -------- VHF P --------- P / VHF -------------- J VHF ---------------------------------------------------------------- ----- ----- Q Q J (b) +D ( ) ;U -+ ----- D ( ) ( ; LQ ) Q P---------------------------- ( ) --------- UDG VHF ----- VHF ;U (c) P PP Since + D ( ) is assumed to be 1 for the accelerometer device for all 's, [ LQ PHDVXUHG Q ;U ( ) P -------- VHF ( ) ( ) WDQ --------------------------------------- (d) ----- Q WDQ ----------------------- ----- Q ; U VLQ ( W ) N 1 --P UDG ------V UDG [U ( W ) 9.19 P Q ;U ----;L NJ N--P VLQ ( W ) PP 1V -----P UDG ------V ;L E ------------- NP P E U ----Q U -----------------------------------------------( U ) U U WDQ -------------- U UDG 72 Introduction to Mechatronics and Meaurement Systems Solutions Manual ;U ; L ----- ; L ;U P Therefore, the steady state output displacement response is: [R ( W ) [R ( W ) [L ( W ) [U ( W ) ; L VLQ ( W ) ; U VLQ ( W ) ( VLQ ( W ) VLQ ( W ) )PP Introduction to Mechatronics and Measurement Systems 73 ...
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