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Unformatted text preview: Math 241. Quiz 6. 3/4/09. Name: 0 Read problems carefully. Show all work.
c There are 15 points total. 1. §14.3, #79 a (7 points): Given f (:12, y) = 3:33;?  21:23; + :17, ﬁnd fmy. fx = 3xgyg4‘xy +1
f“ = (axyf—‘f’y' {my .~. goxy‘t 2. §14.5, #21: Suppose that $23] , m=(uv)”2, y=1/v. 2:6 8::
(a) (5 points): Use an appmpriate form of the chain rule to compute Your answer should be in one or both of the variables u and 1). an
Simplify your answer as much as possible!
J? E 4‘? 23. s 21.226.
x Y 1
222 3A i1 l 9 1 Kay 0* V) '7
3‘“/\ dV 4 :2, RK>/=Q QUAV)
v V 2 x
U. .
“ L4
3 Q Q (A)
1/
..l . '4
O x ‘6 L (A 4, 1. J.)
“" = V "a. ’ ’3' u
’3 v.
, u l ‘4 ‘4
#723; a .ZQA)4._1(M :e.
d 7 a V 2. M
(b) (3 points): If you want to compute Q, what form of the chain rule should you use? 6v
(1 am only asking you to write down the rule, not to apply it.) ...
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This note was uploaded on 09/09/2009 for the course MATH 241 taught by Professor Wolfe during the Spring '08 term at Maryland.
 Spring '08
 Wolfe

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