HW4_explained - padilla(tp5647 HW04 Atomic Theory Part II...

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padilla (tp5647) – HW04: Atomic Theory Part II – shear – (52375) 1 This print-out should have 15 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. The last six questions are on material that will be covered in class on Tuesday. Read section 12.15 and attempt anyhow. 001 10.0 points In a one-dimensional particle in a box, for n = 6, how many wavelengths equals the size of the box? 1. 1 2. 3 correct 3. 12 4. 2.5 5. 6 Explanation: For n = 6 the wavefunction would be x = 0 x = L 002 10.0 points The three quantum numbers for an electron in a hydrogen atom in a certain state are n = 4, = 1, m = 1. The electron is located in what type of orbital? 1. 4 p correct 2. 4 d 3. 3 d 4. 3 p 5. 4 s Explanation: The notation is n , where n = 1 , 2 , 3 , 4 , 5 , ... , = 0 , 1 , 2 , ..., ( n - 1) represented as a letter: 0 1 2 3 4 5 etc. orbital s p d f g h and m = - ℓ, - ( - 1) , - ( - 2) , ..., 0 , ..., +( - 2) , +( - 1) , ℓ . The value of m is not needed to determine the orbital type, as long as it is valid. 003 10.0 points An electron in a 3 d orbital could have which of the following quantum numbers? 1. n = 3; = 2; m = - 3 2. n = 3; = 3; m = 1 3. n = 3; = 1; m = 2 4. n = 3; = 0; m = 0 5. n = 2; = 2; m = 6 6. n = 3; = 1; m = - 1 7. n = 3; = 2; m = 0 correct Explanation: 3 refers to the principal quantum number n . d corresponds to the subsidiary quantum number = 2. Since = 2, m could be - 2 , - 1 , 0 , 1 or 2.
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