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Unformatted text preview: Version 200 – Exam 1 – Sutcliffe – (53770) 1 This print-out should have 30 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. THIS EXAM IS ONLY FOR STUDENTS ENROLLED IN UNIQUE NUMBER 53770 WHICH MEETS T TH 3.30-5PM 001 10.0 points Which of the following statements is NOT true about isotopes of the same element? 1. They always have different atomic weights. 2. They always have the same atomic num- ber. 3. They always have different numbers of protons. correct 4. They always have different numbers of neutrons. Explanation: The number of protons never changes for a given element. 002 10.0 points Which of the following is true about the Bohr atom? 1. It only contained s and p orbitals. 2. It allowed only quantized energy levels. correct 3. It could explain the atomic spectra of He. 4. It was described by 4 quantum numbers. Explanation: 003 10.0 points Choose that pair of names and formulas that do not match. 1. MnCO 3 : manganese(II) carbonate 2. Fe 2 (SO 4 ) 3 : iron(III) sulfate 3. SnCl 4 : tin(IV) chloride 4. SnO : tin(II) oxide 5. Cu 2 O : copper(II) oxide correct Explanation: The copper(II) ion is Cu 2+ ; the oxide ion is O 2- . One O 2- is needed to balance the charge of each Cu 2+ , so the correct formula for copper(II) oxide is CuO. In Cu 2 O, the total charge from copper ions must be +2 to balance the- 2 charge from the oxide ion. Each copper ion would have a charge of +1. This compound is copper(I) oxide. The manganese(II) ion is Mn 2+ ; the car- bonate ion is CO 3 2- . One CO 3 2- is needed to balance the charge of each Mn 2+ , so the formula is MnCO 3 . The tin(IV) ion is Sn 4+ ; the chloride ion is Cl- . Four Cl- are needed to balance the charge of each Sn 4+ , so the formula is SnCl 4 . The tin(II) ion is Sn 2+ ; the oxide ion is O 2- . One O 2- is needed to balance the charge of each Sn 2+ , so the formula is SnO. The iron(III) ion is Fe 3+ ; the sulfate ion is SO 4 2- . Three SO 4 2- are needed to balance the charge of every two Fe 3+ . (This gives a total anion charge of- 6 and a total cation charge of +6.) The formula is Fe 2 (SO 4 ) 3 . 004 10.0 points The photoelectric effect provided evidence for the (wave, particle)-like behavior of light. The phenomenon of diffraction provided evidence for the (wave, particle)-like behavior of light. 1. particle, wave correct 2. particle, particle 3. wave, particle 4. wave, wave Explanation: The photoelectric effect demonstrates par- ticle behavior and diffraction wave behavior. Version 200 – Exam 1 – Sutcliffe – (53770) 2 005 10.0 points Which of the following electron configurations would represent a halogen? 1. [Ne] 3 s 2 3 p 5 correct 2. [He] 2 s 2 2 p 3 3. [Ar] 4 s 1 4. [Ne] 3 s 2 5. [Ar] 3 d 5 4 s 2 Explanation: Halogens are members of Group 7, so this means that they have 7 valence electrons....
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- Spring '09
- Atom, Sutcliffe