CEE460 Exam 1 Solution (Spring 2008)

CEE460 Exam 1 Solution (Spring 2008) - Name 9\qJir"1...

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3/11/08 Problen #1 (20 points) Thebolled connection configuration shown below is at the end ofa plate tension member (A36). Theunfactored tensile loading is: dead load Pp:50 kips, Iive load Pr. = 30 kips, /,/ and wind load Pw:90 kips. -) F., ' 1r, Lr' I PI, lf- /0' Name: 9"\qJir"1 /_'. ^ '\ c.l o.l (\ + P,,, P,., P* ?" -- t,zPo+ osPLr l.LP\i = l.z (5rL\ r o.5GoL) 4 t.ta(9rk) 1. Standard bolt 3/4" bolts ,,7 holes for oramgler -- Llq L a) Compute the factored tensile load, Pu, using the appropriate LRFD load combination and select a plate thickness so that the design tensile strength ofthe plate member, OrPn. is adequate based on the limit states ofyield on the gross area a.nd fracture on the net eff'ective area. Indicate on the figure where.these limit states arc being checked. When specifying the plate thickness, assume that plate is available in l/8" increments. b) With a sketch, indicate a potcntial block shear ruptue path. Does block sheax rupture appear likely to occur for this member? (No calculations arc required,) r) !,rr/r". ,L?^ -^ o,\ E A. -- (D.1)(3{" lJt (6') t I ?... = zrq k - t - 1 1 I > D.944' .'. .hoocr 1' lo lb- Y'{r<u2 t\ F a"nB +tP* . o.?5F,4L A^- bt - adrt +z\$ + zt'i. t ' a (o.zs\ (sv rr; ) ( r o) ( a,:lst) ) .'. y1clJi"1 ."* {wls .Loose /o \--- --:;-l )t = r/6'\ Bgt :,,-q xn\$cty \$ o.cur b) \"(le+i)r .""* ft"u ",r^^' fF^:,tuw p\a"cl +t ll*n g" y*a 4 -tl.a *".iU' pta*9 \-l tr;t ' .ed,-r C i e I **fd? Ds1? { *n +'..w ) .-'.? B s? w,r,,.l "( br I "q r - o't ,1 1ft, r*ni:,".

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• Spring '08
• Abrams

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