OMPhQuiz_06_p46-57 - chapter 6 Further Applications of...

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46 PhysiQuiz Contents Friction (Section 6.1) 1. Two blocks 2. Moving along the ceiling 3. Pulling at an angle 4. Sliding down an incline with friction 5. Blocks and pulley with friction Spring force: Hooke’s Law (Section 6.2) 6. N identical springs in series Uniform circular motion (Section 6.3) 7. Conic pendulum 8. Car on a curve Additional conceptual exercises for circular motion and Section 6.3 9. A Ferris wheel 10. Within a cyclone 11. A spinning toy chapter 6 Further Applications of Newton’s Laws
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A two-block system experiences a horizontal applied force as shown here. Denote the force exerted on block 2 by block 1 as F 21 . The coefficients of kinetic friction between block 1 and block 2 and the surface are m 1 and m 2 respectively. If the acceleration of the system is a , then the equation of motion given by Newton’s Second Law for block 2 is given by which of the following? A F 2 m 1 m 1 g 2 m 2 m 2 g 5 m 2 a B F 21 2 m 2 m 2 g 5 m 2 a C F 1 F 21 2 m 2 m 2 g 5 m 2 a Explanation: The net force on block 2 is F 21 2 m 2 m 2 g . Applying Newton’s Second Law, F net 5 ma , leads to Answer 5 B. Block 1 m 1 1 μ 2 F Block 2 m 2 1. Two Blocks PhysiQuiz 47
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The force F exerted on the block pushes the block against the ceiling and at the same time accelerates the block to the right. Find the force of the kinetic friction between the block and the ceiling: AB C D f k m k mg m k F sin um k ( F sin u 2 mg ) m k ( F sin u 1 mg ) Explanation: The net normal force between the block and the ceiling is N 5 F sin u 2 mg . So the force of kinetic friction is f k 5 m k N 5 m k ( F sin u 2 mg ). Answer 5 C. F θ 48 PhysiQuiz 2. Moving Along the Ceiling
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The diagram here shows a block of mass m 5 1 kg being pulled by force F , where F x 5 8 N and F y 5 6 N. The block is on a horizontal surface, and the coefficients of friction between the block and the surface are m s 5 0.7 and m k 5 0.5. Use this information to find the force of friction f on the block: A f 5 F x 5 8 N B f 5 m s ( mg 2 F y ) 5 0.7 3 4 5 2.8 N C f 5 m k mg 5 0.5 3 10 5 5 N D f 5 m k ( mg 2 F y ) 5 0.5 3 4 5 2 N Hint: N 5 mg 2 F y 5 1 3 10 2 6 5 4 N, f s,max 5 m s N 5 0.7 3 4 5 2.8 N. Should the friction be f s 5 F x or f k 5 m k N ? Extra: Determine the acceleration of the block.
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OMPhQuiz_06_p46-57 - chapter 6 Further Applications of...

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