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Unformatted text preview: ) 1 2 $ % & ’ ( ) sin 2 L x $ % & ’ ( ) * + ,. / = 2 2 5 L sin L x $ % & ’ ( ) 2 5 L sin 2 L x $ % & ’ ( ) = 2 2 5 L L 2 2 L sin L x $ % & ’ ( ) 2 5 L L 2 2 L sin 2 L x $ % & ’ ( ) = 2 2 5 L L 2 " 1 ( x , t = 0) 2 5 L L 2 " 2 ( x , t = 0) = 2 1 5 " 1 ( x , t = 0) 1 5 " 2 ( x , t = 0) = 4 5 " 1 ( x , t = 0) 1 5 " 2 ( x , t = 0) Yikes! Notice that c 1 = 4 5 and c 2 = 1 5 and c 1 2 + c 2 2 = 1. Finally, we can answer the question: " ( x , t ) = 4 5 " 1 ( x , t ) # 1 5 " 2 ( x , t ) = 4 5 $ 1 ( x ) % 1 ( t ) # 1 5 2 ( x ) 2 ( t ) . 2. This takes a while and will be done later in the course. GRE Practice #4: 42B, 60B, 51B, 98D....
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 Spring '09
 Sin, Livestock, CAMEL, Bactrian camel, Camelid, Dromedary

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