HW3_P30_corrected

HW3_P30_corrected - • http/www.cachesoftware.com/mopac/Mopac2002manual/node589.html • http/en.wikipedia.org/wiki/Reduced_mass •

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Correction to HW 3 Solutions - #30 You may need to know the following info in the future so be sure to examine this. Chapter 6 Problem 30 – corrected C = μ " 2 , where is the reduced mass = m 1 m 2 m 1 + m 2 = M total 4 , in this problem with equal masses. So, = C = 3.12x10 14 . E = 1 2 h = 1.64x10 -20 J = 0.102 eV. For more information on reduced mass, see
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: • http://www.cachesoftware.com/mopac/Mopac2002manual/node589.html • http://en.wikipedia.org/wiki/Reduced_mass • http://www.everyscience.com/Chemistry/Physical/Vibrational_Spectroscopy/a.10 19.php...
View Full Document

This document was uploaded on 09/10/2009.

Ask a homework question - tutors are online