# Ma316f03hw2 - MA 316 MATHEMATICAL PROBABILITY ASSIGNMENT#2 SOLUTIONS SECTION 1.4 FALL 2003 1.34 For part a notice that the event in which the

This preview shows pages 1–2. Sign up to view the full content.

MA 316: MATHEMATICAL PROBABILITY ASSIGNMENT #2: SOLUTIONS: SECTION 1.4 FALL 2003 1.34: For part a), notice that the event in which the colors alternate occurs only if we choose from the bowl either RBRB or BRBR in these orders. Since the probability of the ﬁrst outcome is 3 8 5 7 2 6 4 5 and the probability of the second outcome is 5 8 3 7 4 6 2 5 , then the probability of the desired event is the sum of these values which is 1 / 7. For part b), notice that the only way in which we can obtain the ﬁrst blue chip on the third draw is if we choose from the bowl RRB in that order, and this event has probability 3 8 2 7 5 6 = 5 56 . 1.35: If B denotes the event in which we are dealt at least 3 kings in our hand of 13 cards and A the event we are dealt at least two kings, then we are asked to compute the conditional probability P ( B | A ) = P ( A B ) /P ( A ) = P ( B ) /P ( A ) . Since P ( B ) = £( 4 3 )( 48 10 ) + ( 4 4 )( 48 9 )/ ( 52 13 ) and P ( A ) = £( 4 2 )( 48 11 ) + ( 4 3 )( 48 10 ) + ( 4 4 )( 48 9 )/ ( 52

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

## This note was uploaded on 09/10/2009 for the course STATS 517 taught by Professor Song during the Fall '07 term at Purdue University-West Lafayette.

### Page1 / 2

Ma316f03hw2 - MA 316 MATHEMATICAL PROBABILITY ASSIGNMENT#2 SOLUTIONS SECTION 1.4 FALL 2003 1.34 For part a notice that the event in which the

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online