Stoichiometry_Fall_06

# Stoichiometry_Fall_06 - Stoichiometry Reactions and...

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Stoichiometry: Reactions and Limiting Reagents © Regents of the University of California, 2006. Stoichiometry REACTIONS AND LIMITING REAGENTS Stoichiometry involves using a balanced chemical equation to determine mass and mole relationships. For example, consider the chemical equation for the reaction of C 3 H 8 (propane) with O 2 (oxygen) to form CO 2 (carbon dioxide) and H 2 O (water): C 3 H 8 + 5 O 2 3 CO 2 + 4 H 2 O We can interpret the equation as follows: Counting on the atomic scale : One molecule of propane and five molecules of oxygen are consumed for every three molecules of carbon dioxide and four molecules of water produced. Counting on the macroscopic scale : One mole of propane and five moles of oxygen are consumed for every three moles of carbon dioxide and four moles of water produced. Weighing: 44 grams of propane and 160 grams of oxygen are consumed for every 132 grams of carbon dioxide and 72 grams of water produced. In this discussion sheet, we will examine the amounts (both moles and grams) of products obtained for various ratios of reactants. Thinking about it: Why don’t the moles of product always double when the moles of one reactant are doubled? INITIAL IDEAS (answer on your own, then participate in a class discussion) Baking soda (NaHCO 3 ) and vinegar (CH 3 COOH) react to generate carbon dioxide gas: CH 3 COOH(aq)+ NaHCO 3 (s) NaCH 3 COO(aq) + H 2 O(l) + CO 2 (g) You decide to mix various amounts of baking soda and vinegar together and measure the amount of

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Stoichiometry_Fall_06 - Stoichiometry Reactions and...

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