This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: process, since the system returns to the same state ΔH=0, but q need not be 0. More generally while dH=dq, but 1 2 2 1 H H dH H= = ∆ ∫ (state function) 1 2 2 1 q q dq q≠ = ∫ (path function) 3. The system below has infinite number of equally spaced energy levels. There are two possible states for every energy level. What will be the multiplicity of the system if the total energy, U=ne and there are two particles in the system (3) .......................................... 5e_________ _________ 4e_________ _________ 3e_________ _________ 2e_________ _________ e_________ _________ 0_________ _________ Solution: W = W positional X W energy W energy = (n+1) (There are n+1 ways of distributing n.e of energy between two particles in this system – see quiz 3A) W positional = 2 X 2 (Each particle can be in two equivalent positions.) =4 W = W positional X W energy =4(n+1)...
View
Full Document
 Fall '09
 Kuryian
 Thermodynamics, Entropy, ........., negative heat capacity

Click to edit the document details