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Unformatted text preview: process, since the system returns to the same state H=0, but q need not be 0. More generally while dH=dq, but 1 2 2 1 H H dH H-= = (state function) 1 2 2 1 q q dq q- = (path function) 3. The system below has infinite number of equally spaced energy levels. There are two possible states for every energy level. What will be the multiplicity of the system if the total energy, U=ne and there are two particles in the system (3) .......................................... 5e_________ _________ 4e_________ _________ 3e_________ _________ 2e_________ _________ e_________ _________ 0_________ _________ Solution: W = W positional X W energy W energy = (n+1) (There are n+1 ways of distributing n.e of energy between two particles in this system see quiz 3A) W positional = 2 X 2 (Each particle can be in two equivalent positions.) =4 W = W positional X W energy =4(n+1)...
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This note was uploaded on 09/14/2009 for the course MCB 100A taught by Professor Kuryian during the Fall '09 term at University of California, Berkeley.
- Fall '09